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    What is the smallest number divisible by 1 20?What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20 answer?What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20 in node JS?What is the smallest positive number that is evenly divisible by all of the numbers from A to B?

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Given a number n find the smallest number evenly divisible by each number 1 to n.
Examples: 
 

Input : n = 4
Output : 12
Explanation : 12 is the smallest numbers divisible
by all numbers from 1 to 4
Input : n = 10
Output : 2520
Input : n = 20
Output : 232792560

If you observe carefully the ans must be the LCM of the numbers 1 to n
To find LCM of numbers from 1 to n – 
 

Initialize ans = 1. 
 Iterate over all the numbers from i = 1 to i = n. 
At the i’th iteration ans = LCM(1, 2, …….., i). This can be done easily as LCM(1, 2, …., i) = LCM(ans, i)
Thus i’th iteration we just have to do – 
 
ans = LCM(ans, i)
= ans * i / gcd(ans, i) [Using the below property,
a*b = gcd(a,b) * lcm(a,b)] 

Note : In C++ code, the answer quickly exceeds the integer limit, even the long long limit.
Below is the implementation of the logic. 
 

C++

#include

using namespace std;

long long lcm(long long n)

    long long ans = 1;   

    for (long long i = 1; i <= n; i++)

        ans = (ans * i)/(__gcd(ans, i));

    return ans;

int main()

    long long n = 20;

    cout << lcm(n);

    return 0;

Java

 class GFG

static long gcd(long a, long b)

   if(a%b != 0)

      return gcd(b,a%b);

   else

      return b;

static long lcm(long n)

    long ans = 1;   

    for (long i = 1; i <= n; i++)

        ans = (ans * i)/(gcd(ans, i));

    return ans;

public static void main(String []args)

    long n = 20;

    System.out.println(lcm(n));

C#

using System;

public class
GFG

    static long gcd(long a, long b)

if(a%b != 0)

    return gcd(b,a%b);

else

    return b;

static long lcm(long n)

    long ans = 1;    

    for (long i = 1; i <= n; i++)

        ans = (ans * i)/(gcd(ans, i));

    return ans;

    static public void Main ()

        long
n = 20;

        Console.WriteLine(lcm(n));

    

Python3

import math

def lcm(n):

    ans = 1

    for i in range(1, n + 1):

        ans = int((ans * i)/math.gcd(ans, i))        

    return ans

n = 20

print (lcm(n))

PHP

<?php

function lcm($n)

    $ans = 1;

    for ($i = 1; $i <= $n; $i++)

        $ans = ($ans * $i) / (gmp_gcd(strval(ans),

                                      strval(i)));

    return $ans;

$n = 20;

echo lcm($n);

?>

Javascript

function gcd(a, b)

   if(a%b != 0)

      return gcd(b,a%b);

   else

      return b;

function lcm(n)

    let ans = 1;   

    for (let i = 1; i <= n; i++)

        ans = (ans * i)/(gcd(ans, i));

    return ans;

    let n = 20;

    document.write(lcm(n));

Output : 

232792560

The
above solution works fine for a single input. But if we have multiple inputs, it is a good idea to use Sieve of Eratosthenes to store all prime factors. Please refer below article for Sieve based approach. 
LCM of First n Natural Numbers
This article is contributed by Ayush
Khanduri
. If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to . See your article appearing on the GeeksforGeeks main page and help other Geeks.
 

What is the smallest number divisible by 1 20?

2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder.

What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20 answer?

I want to print the smallest number that is evenly divisible by all of the numbers from 1 to 20. The code is correct. If you enter i = 2432902008176640000 , it will finish immediately.

What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20 in node JS?

For example, the smallest positive number for 1 – 20 is 232,792,560.

What is the smallest positive number that is evenly divisible by all of the numbers from A to B?

The answer is 1. Any single-digit number is divisible by all its digits.
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