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## Mẹo về Smallest positive number that is evenly divisible by all of the numbers from 1 to 20 Python 2022

Bạn đang tìm kiếm từ khóa Smallest positive number that is evenly divisible by all of the numbers from 1 to 20 Python được Update vào lúc : 2022-10-10 08:07:14 . Với phương châm chia sẻ Bí quyết về trong nội dung bài viết một cách Chi Tiết 2022. Nếu sau khi tìm hiểu thêm Post vẫn ko hiểu thì hoàn toàn có thể lại Comment ở cuối bài để Mình lý giải và hướng dẫn lại nha.

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What is the smallest number divisible by 1 20?What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20 answer?What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20 in node JS?What is the smallest positive number that is evenly divisible by all of the numbers from A to B?

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Given a number n find the smallest number evenly divisible by each number 1 to n.
Examples:

Input : n = 4
Output : 12
Explanation : 12 is the smallest numbers divisible
by all numbers from 1 to 4
Input : n = 10
Output : 2520
Input : n = 20
Output : 232792560

If you observe carefully the ans must be the LCM of the numbers 1 to n
To find LCM of numbers from 1 to n –

Initialize ans = 1.
Iterate over all the numbers from i = 1 to i = n.
At the i’th iteration ans = LCM(1, 2, …….., i). This can be done easily as LCM(1, 2, …., i) = LCM(ans, i)
Thus i’th iteration we just have to do –

ans = LCM(ans, i)
= ans * i / gcd(ans, i) [Using the below property,
a*b = gcd(a,b) * lcm(a,b)]

Note : In C++ code, the answer quickly exceeds the integer limit, even the long long limit.
Below is the implementation of the logic.

## C++

#include

using namespace std;

long long lcm(long long n)

long long ans = 1;

for (long long i = 1; i <= n; i++)

ans = (ans * i)/(__gcd(ans, i));

return ans;

int main()

long long n = 20;

cout << lcm(n);

return 0;

## Java

class GFG

static long gcd(long a, long b)

if(a%b != 0)

return gcd(b,a%b);

else

return b;

static long lcm(long n)

long ans = 1;

for (long i = 1; i <= n; i++)

ans = (ans * i)/(gcd(ans, i));

return ans;

public static void main(String []args)

long n = 20;

System.out.println(lcm(n));

## C#

using System;

public class
GFG

static long gcd(long a, long b)

if(a%b != 0)

return gcd(b,a%b);

else

return b;

static long lcm(long n)

long ans = 1;

for (long i = 1; i <= n; i++)

ans = (ans * i)/(gcd(ans, i));

return ans;

static public void Main ()

long
n = 20;

Console.WriteLine(lcm(n));

## Python3

import math

def lcm(n):

ans = 1

for i in range(1, n + 1):

ans = int((ans * i)/math.gcd(ans, i))

return ans

n = 20

print (lcm(n))

## PHP

<?php

function lcm(\$n)

\$ans = 1;

for (\$i = 1; \$i <= \$n; \$i++)

\$ans = (\$ans * \$i) / (gmp_gcd(strval(ans),

strval(i)));

return \$ans;

\$n = 20;

echo lcm(\$n);

?>

## Javascript

function gcd(a, b)

if(a%b != 0)

return gcd(b,a%b);

else

return b;

function lcm(n)

let ans = 1;

for (let i = 1; i <= n; i++)

ans = (ans * i)/(gcd(ans, i));

return ans;

let n = 20;

document.write(lcm(n));

Output :

232792560

The
above solution works fine for a single input. But if we have multiple inputs, it is a good idea to use Sieve of Eratosthenes to store all prime factors. Please refer below article for Sieve based approach.
LCM of First n Natural Numbers
Khanduri
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### What is the smallest number divisible by 1 20?

2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder.

### What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20 answer?

I want to print the smallest number that is evenly divisible by all of the numbers from 1 to 20. The code is correct. If you enter i = 2432902008176640000 , it will finish immediately.

### What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20 in node JS?

For example, the smallest positive number for 1 – 20 is 232,792,560.

### What is the smallest positive number that is evenly divisible by all of the numbers from A to B?

The answer is 1. Any single-digit number is divisible by all its digits.
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