Hướng Dẫn Compare each element in List Java Chi tiết

Contents

1 Thủ Thuật Hướng dẫn Compare each element in List Java Chi Tiết
2 Compare ArrayLists using Equal():
- 2.1 Source Code:
- 2.2 Output:
3 Compare Arraylists using retainAll():
- 3.1 Source code:
- 3.2 Output:
4 Compare ArrayLists using contains():
- 4.1 Source code:
- 4.2 Output:
5 References:
- 5.1 Video Compare each element in List Java ?
- 5.2 Chia Sẻ Link Tải Compare each element in List Java miễn phí
  - 5.2.1 Hỏi đáp vướng mắc về Compare each element in List Java

Thủ Thuật Hướng dẫn Compare each element in List Java Chi Tiết

You đang tìm kiếm từ khóa Compare each element in List Java được Cập Nhật vào lúc : 2022-03-13 05:03:20 . Với phương châm chia sẻ Thủ Thuật về trong nội dung bài viết một cách Chi Tiết 2022. Nếu sau khi Read nội dung bài viết vẫn ko hiểu thì hoàn toàn có thể lại Comments ở cuối bài để Tác giả lý giải và hướng dẫn lại nha.

Comparing two ArrayLists could be a tricky task for beginner programmers. On this page, we are going to share some of the best ways to compare two ArrayLists.

Nội dung chính

Compare ArrayLists using Equal():Source Code:Compare Arraylists using retainAll():Source code:Compare ArrayLists using contains():Source code:References:

Compare ArrayLists using Equal():

You can easily compare the two ArrayLists by simply using the equals() method. This method returns a boolean value(True or False). So, if the result is true, the ArrayLists are equal; otherwise, they are not equal.

Source Code:

import java.util.ArrayList;

public class ComparingArrayLists //using equals()

public static void main(String[] args)
//initializing two array lists
ArrayList list1 = new ArrayList ();
ArrayList list2 = new ArrayList ();

//storing data in list 1
list1.add(“Java”);
list1.add(“Python”);
list1.add(“C++”);

//storing data in list 2
list2.add(“Java”);
list2.add(“Python”);
list2.add(“C++”);

//printing both lists
System.out.println(“List 1:” + list1);
System.out.println(“List 2:” + list2);

//comparing both lists
if (list1.equals(list2))
System.out.println(“Lists are equal”);
else
System.out.println(“Lists are not equal”);

//adding another element to list 1
list1.add(“HTML”);

//comparing both lists again
if (list1.equals(list2))
System.out.println(“Lists are equal”);
else
System.out.println(“Lists are not equal”);

Output:

run:
List 1:[Java, Python, C++]
List 2:[Java, Python, C++]
Lists are equal
Lists are not equal
BUILD SUCCESSFUL (total time: 5 seconds)

Compare Arraylists using retainAll():

In case you want to compare two ArrayLists with respect to common elements, then you should be trying retainAll() method. It will return all common elements between two ArrayLists.

Source code:

import java.util.ArrayList;

public class ComparingArrayLists //using retainAll()

public static void main(String[] args)
//initializing two array lists
ArrayList list1 = new ArrayList();
ArrayList list2 = new ArrayList();

//storing data in list 1
list1.add(“Mike”);
list1.add(“Sara”);
list1.add(“John”);

//storing data in list 2
list2.add(“Mike”);
list2.add(“Sara”);
list2.add(“Diaz”);
list2.add(“Sam”);

//printing both lists
System.out.println(“List 1:” + list1);
System.out.println(“List 2:” + list2);

//it will return common elements
list2.retainAll(list1);
//printing common elements
System.out.println(“Common elements are: ” + list2);

Output:

run:
List 1:[Mike, Sara, John]
List 2:[Mike, Sara, Diaz, Sam]
Common elements are: [Mike, Sara]
BUILD SUCCESSFUL (total time: 14 seconds)

Compare ArrayLists using contains():

An alternate way of retainAll() is to compare the elements of the ArrayLists using contains() method. The contains() method checks whether List 1 has the same element as List 2 the same index.

Source code:

import java.util.ArrayList;
import java.util.Arrays;

public class ComparingArrayLists //using contains()

public static void main(String[] args)
//initializing two array lists
ArrayList list1 = new ArrayList(Arrays.asList(“Apple”, “Banana”, “Peach”, “Apricot”));
ArrayList list2 = new ArrayList(Arrays.asList(“Cabbage”, “Carrots”, “Cucumber”, “Banana”));

//printing both lists
System.out.println(“List 1:” + list1);
System.out.println(“List 2:” + list2);

//Finding similar items in both lists
int i=0;
while(i<list1.size() && i<list2.size())
if(list2.contains(list1.get(i)))
System.out.println(list1.get(i) + " is in both lists");

i++;

Output:

run:
List 1:[Apple, Banana, Peach, Apricot]
List 2:[Cabbage, Carrots, Cucumber, Banana]
Banana is in both lists
BUILD SUCCESSFUL (total time: 7 seconds)

References:

Happy Learning ?

Ok, I’m getting a little confused on how to do this. Basically i got N stacks of cards. And need to check the topCard of every stack and check that N – 1 cards match then remove them.

I peeked every stack of cards to get the top card, and added them to an arraylist. But I’m not sure how to go through the arraylist to check that n-1 match or not. (Each card has a getCard method which returns the number then suite as a String (2 Hearts or Ace Diamonds).
(both suite and number have to match)

I’m just getting a bit confused on the best/most efficient way of implementing this.

java

Video Compare each element in List Java ?

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Chia Sẻ Link Tải Compare each element in List Java miễn phí

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Hỏi đáp vướng mắc về Compare each element in List Java

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